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#1
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I don't like the snippet. You didn't give a real explanation.
0x00A89010 -> This memory is dynamically allocated. This can change with every process start. Using this as hardcoded address doesn't seem smart. Why do you read and write 12 bytes? You need only 2 (5) bytes. It even looks like you don't need a 2nd ReadProcessMemory. If it is unpacked, it is unpacked. Why check it 2 times?
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#2
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Quote:
I do agree that memory addresses change which wouldnt work properly. However you dont need to use memory addresses. Code:
ReadProcessMemory(procInfo.hProcess, (LPVOID)0x00409605, buffer, 12, &nSize);
if ((buffer[0] == 0xF6) && (buffer[1] == 0xC1))
{
ReadProcessMemory(procInfo.hProcess, 0x409615, buffer2, 12, &nSize);
if ((buffer2[0] == 0x74) && (buffer2[1] == 0x0C))
{
buffer2[0] = 0x90;
buffer2[1] = 0x90;
//buffer2[2] = 0x01;
//buffer2[3] = 0xEB;
//buffer2[4] = 0x0B;
//buffer2[5] = 0x90;
//buffer2[6] = 0x90;
//buffer2[7] = 0x50;
//Sleep(570);
printf("Address FOUND and patched!\n");
WriteProcessMemory(procInfo.hProcess, ADDRESS2, buffer2, 12, &nSize);
}
If you don't like the way i did it, then make it better and post it here so that people can benefit from your inputs. I agree on that you should dynamically set the bytes. I do two ReadProcessMemory to make sure I'm at the correct place. It's just something slapped together fast, and it works which is the most important thing for me. I'm not a good coder so, I do thank you for your constructive feedback and i'm sorry if it doesnt appeal to your coding ideology Please do your thing and post a better one, im sure both me and the community would be pleased. Have a good day
Last edited by 0x22; 10-20-2014 at 00:26. |
| The Following User Gave Reputation+1 to 0x22 For This Useful Post: | ||
mr.exodia (10-20-2014) | ||
| The Following User Says Thank You to 0x22 For This Useful Post: | ||
niculaita (08-30-2016) | ||
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